(x^2+2x-3)-(x^2+3x+5)=

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Solution for (x^2+2x-3)-(x^2+3x+5)= equation:


Simplifying
(x2 + 2x + -3) + -1(x2 + 3x + 5) = 0

Reorder the terms:
(-3 + 2x + x2) + -1(x2 + 3x + 5) = 0

Remove parenthesis around (-3 + 2x + x2)
-3 + 2x + x2 + -1(x2 + 3x + 5) = 0

Reorder the terms:
-3 + 2x + x2 + -1(5 + 3x + x2) = 0
-3 + 2x + x2 + (5 * -1 + 3x * -1 + x2 * -1) = 0
-3 + 2x + x2 + (-5 + -3x + -1x2) = 0

Reorder the terms:
-3 + -5 + 2x + -3x + x2 + -1x2 = 0

Combine like terms: -3 + -5 = -8
-8 + 2x + -3x + x2 + -1x2 = 0

Combine like terms: 2x + -3x = -1x
-8 + -1x + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
-8 + -1x + 0 = 0
-8 + -1x = 0

Solving
-8 + -1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -1x = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -1x = 0 + 8
-1x = 0 + 8

Combine like terms: 0 + 8 = 8
-1x = 8

Divide each side by '-1'.
x = -8

Simplifying
x = -8

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